(2x+4)(x+2)=2x^2+4x+16

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Solution for (2x+4)(x+2)=2x^2+4x+16 equation: 



(2x+4)(x+2)=2x^2+4x+16

We move all terms to the left:

(2x+4)(x+2)-(2x^2+4x+16)=0

We get rid of parentheses

-2x^2+(2x+4)(x+2)-4x-16=0

We multiply parentheses ..

-2x^2+(+2x^2+4x+4x+8)-4x-16=0

We get rid of parentheses

-2x^2+2x^2+4x+4x-4x+8-16=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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